The fracture toughness of a stainless steel is 137 MPa*m12. What is the tensile impact load sustainable before fracture that a rod can withstand with a pre-existing surface crack of 2 mm, given a square cross-section of 4.5 mm on each side, in kiloNewtons

7.7 kN

Explanation:

The capacity of a material having a crack to withstand fracture is referred to as fracture toughness.

It can be expressed by using the formula:

where;

fracture toughness K = 137 MPa

geometry factor Y = 1

applied stress = ???

crack length a = 2mm = 0.002

∴

Now, the tensile impact obtained is:

P = A × σ

P = 1728.289 × 4.5

P = 7777.30 N

P = 7.7 kN

can you make it more obvious. i can't see it properly