If a cylindrical part with a length of 20 mm and a diameter of 20 mm is to be machined to a cylindrical part with 18 mm in diameter with the same length. The machine has a mechanical efficiency of 50% and a power of 80 kW. If the cutting rake angle is 0 degrees and the cutting tool is made of uncoated carbides and the cutting speed is 10 m/s. What material can we choose for the cylinder

Titanium Alloy

Explanation:

Length ( L ) = 20 mm

D1 = 20 mm

d2 = 18 mm

l = 20 mm

Mechanical efficiency = 50%

power = 80 kW

cutting rake angle = 0°

cutting speed ( v ) = 10 m/s

Determine the material to be for the cylinder

In order to choose a material for the cylinder we have to calculate the cutting force

P = Fc * V

80  = Fc * 10 m/s

therefore Fc = 80 / 10 = 8 N

Hence the material we can use is Titanium Alloy   due to low cutting force value

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explanation: