What is the impedance of a transformer coil that has 600 feet of #22 awg copper with a resistance of 10 ω and an inductance of 0.06 h on 60 hz? calculate to one decimal place.

The impedance of transformer coil that has 600 feet is 10+j 22.62 Ω (ohms)

Explanation:

It is given that

a #22 copper wire has resistance= R= 10 Ω

                                       inductance= I=0.06 H

                                                             N=60 HZ

X= 2π * N * I

=2 * 3.14 * 60 *0.06

X=22.62 Ω

Impedance is calculated by

Z = R + j * X

=10+ j (22.62 Ω)

Z= 10+ j 22.62 Ω

The impedance of a transformer coil that has 600 feet is  Z= 10+ j 22.62 Ω

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