An orange fruit drops to the ground from the top of a tree 45m tall. how Long does it take to reach the ground?(10m/s)

3 seconds

Explanation:

Height(S) of tree = 45m

Acceleration due to gravity (g) = 10m/s^2

From second equation of motion:

S = ut + 0.5at^2

Where:

u = initial velocity ; t = time taken ; a = acceleration due to gravity; S = distance or height

Here u = 0

S = ut + 0.5at^2

Plugging our values :

45 = 0(t) + 0.5(10)(t^2)

45 = 0 + 5t^2

5t^2 = 45

t^2 = 45 / 5

t^2 = 9

Taking the square root of both sides

t = 3s

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