Calculate and compare the amount of energy retrieved by the ocean and by the atmosphere. assume that the radius of the area is 1 m, and the density of seawater is 1028 kg m-3 and of air is 1.29 kg m-3. also, assume that the mean flow in the atmosphere is 10 m s-1 whereas that of the ocean is 1 m s-1.

for atmosphere K.E. = 0.5 × 1.29 × 10²

for atmosphere K.E. = 64.5 J

so we can say atmosphere is moving faster

and  amount of energy is significantly less than that is possessed by ocean of same volume

Explanation:

given data

radius of the area = 1 m

density of seawater = 1028 kg/m³

density of air = 1.29 kg/m³

mean flow atmosphere = 10 m/s

mean flow ocean = 1 m/s

to find out

Calculate and compare the amount of energy retrieved by the ocean and by the atmosphere

solution

we know that here kinetic energy is express as

K.E. = 0.5 × m× v²

here m is mass and v is velocity

but we take m = dv and where d is density and v is volume  

so

K.E. = 0.5 × dv × v²     1

and here we know side is 1 m

so volume will be =  1 m³

and dv is given = 1028 for ocean and 1.29 for atmosphere

so from equation 1

for ocean K.E. = 0.5 × 1028 × 1²

for ocean K.E. = 514 J

and

for atmosphere K.E. = 0.5 × 1.29 × 10²

for atmosphere K.E. = 64.5 J

so we can say atmosphere is moving faster

and  amount of energy is significantly less than that is possessed by ocean of same volume