Uculating the Perimeter of a Triangle GO
y
Triangle ABC is an isosceles triangle in which side
AB = AC. What is the perimeter of triangle ABC?
5
4
O 5+ 10 units
3
2
O 10 + 10 units
1
2
10/10 units
2.
3
- 5 4 -3 -2 -1
-1
4
5
O 50 units
B
-2
А
c
-5

Complete question.

Kindly view the omitted graph in the picture attached.

10 + √10

Explanation:

Given that the triangle is an isosceles triangle, such that AB = AC

TO CALCULATE SEGMENT AB:

From the graph ;

A(-2,-4) and B(2,-1)

AB = sqrt[(2 - - 2)^2 + (-1 - - 4)^2

AB = sqrt[4^2 + 3^2]

AB = sqrt(16 + 9)

AB = 5

Therefore, AB = AC = 5 Units

To get segment BC:

Coordinates of B(2,-1) and C(3,-4)

BC = sqrt[(3 - 2)^2 + (-4 - - 1)^2

BC = sqrt[1^2 + -3^2]

BC = sqrt(1 + 9)

BC = √10

The perimeter is therefore,

AB + AC + BC

5 + 5 + √10

= 10 + √10