Find the perimeter of the polygon with the vertices UC - 2, 4), V(3, 4), and W(3. – 4).

Find the perimeter of the polygon with the vertices UC - 2, 4), V(3, 4), and W(3. – 4).

Explanation:

this is a right triangle, where one angle is 90 degrees. Two sides are perpendicular to each other.

U to V have the same y values so the distance is the difference in x values or 3 - (-2) = 5

V to W have the same x values, so the distance is the difference in y values or 4-(-4) = 8

U to W is the hypotenuse of the right triangle, = sqr(sum of squares of the other 2 sides) = sqr(25+64)=sqr(89)

Perimeter = sum of the 3 sides = 5 + 8 + sqr(89) = 13 + sqr89 = 13 + 9.44 = 22.44

81 is 9 squared.  100 is 10 squared.  91 is about 9.5 squared.  Rounded to 2 decimal places, it's 9.44

It might help if you plot the 3 points on a graph. That makes it clear you're dealing with a right triangle.

Or if you want, you could have used the distance formula on all 3 sides, but it simplifies to the above.