Find d(21) in the sequence given by d(n) = 2+0.4(n-1). d(21)=

8

Explanation:

From the question, we are informed that we should find d(21) in the sequence given by d(n) = 2+0.4(n-1). This will be:

d(n) = 2+0.4(n-1)

d(21) = 2 + 0.4(21 - 1)

= 2 + 0.4(20)

= 2 + 8

= 10

Therefore, based on the above calculation, we can deduce that the 21st term is 8.