Find the perimeter of a quadrilateral with vertices at C (−2, 4), D (−3, 1), E (1, 0), and F (−1, 2). Round your answer to the nearest hundredth when necessary. 10 units
10.77 units
11.52 units
12.35 units

Perimeter of quadrilateral =  12.35 units

Explanation:

To find - Find the perimeter of a quadrilateral with vertices at C (−2, 4), D (−3, 1), E (1, 0), and F (−1, 2).

Proof -

The figure becomes :

We have the points -

C (−2, 4),

D (−3, 1),

E (1, 0),

F (−1, 2)

Now,

We know that -

The perimeter = Distance of (CD + DE + EF + FC)

Now,

Distance of CD = √(-3 + 2)² + (1 - 4)²

                         = √(-1)² + (-3)²

                         = √1 + 9

                         = √10 = 3.16

⇒Distance of CD = 3.16

Now,

Distance of DE = √(1 + 3)² + (0 - 1)²

                         = √(4)² + (-1)²

                         = √16 + 1

                         = √17 = 4.12

⇒Distance of DE = 4.12

Now,

Distance of EF = √(-1 - 1)² + (2 - 0)²

                         = √(-2)² + (2)²

                         = √4 + 4

                         = √8 = 2.83

⇒Distance of EF = 2.83

Now,

Distance of FC = √(-2 + 1)² + (4 - 2)²

                         = √(-1)² + (2)²

                         = √1 + 4

                         = √5 = 2.24

⇒Distance of FC = 2.24

So,

Perimeter of quadrilateral = 3.16 + 4.12 + 2.83 + 2.24

                                           = 12.35 units

⇒Perimeter of quadrilateral =  12.35 units

the answer is:

c. islam and christianity

explanation:

islam and christianity are widely practiced in africa. islam is practiced due to its spread from the middle east into africa, and christianity is practiced due to the colonization of africa by the british empire.