Given: ΔABC with AD:DB = CE:EB Prove DE||AC
1. AD:DB = CE:EB Given
2. AD:DB+1 = CE:EB...
Geography, 26.11.2021 04:30 mjasmine3280
Given: ΔABC with AD:DB = CE:EB Prove DE||AC
1. AD:DB = CE:EB Given
2. AD:DB+1 = CE:EB+1 Addition Property of Equality
3. (AD+DB)/DB = (CE+EB)/EB Using common denominators
4. AB = AD+ DB and CB = CE +EB segment addition
5. AB:DB = CB:EB Substitution property of equality
6. [Fill in missing statement from choices below] Reflexive property of congruence
7. ΔABC ~ ΔDBE SAS similarity criterion
8. ∠BAC ≅ ∠BDE Corresponding angles of similar triangles are congruent.
9. DE||AC If the corresponding angles formed by two lines cut by a transversal are congruent, then the lines are parallel.
What is the missing step in this proof?
A. ∠ABC ≅ ∠DBE
B. ∠BCA ≅ ∠BDE
C. ∠ACB ≅ ∠DEB
D. ∠BDE ≅ ∠ADE
E. ∠CAB ≅ ∠DAC
I got this wrong on the test and I don't know what I did wrong.
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