If 300cm ^3 of N2(g) (Nitrogen gas) diffuses through a porous partition in 25 seconds, what volume of Cl2(g) (Chlorine gas) will diffuse through the same partition at the same time (N=14, Cl=35.5)

188.40cm^3

Explanation:

Given the following :

FOR N2 gas:

Volume (V) = 300cm^3

Time(t) = 25s

Molar mass (M) = (14 × 2) = 28

FOR Cl2:

Volume (V) =?

Time(t) = 25s

Molar mass (M) = (35.5 × 2) = 71

According to graham's law of diffusion:

V/t = k(1/√M)

Where k is the constant of proportionality

For N2:

300/25 = k(1/√28) - - - - - (1)

For Cl2:

V/25 = k(1/√71) - - - - - - - (2)

Dividing 1 and 2

(300/25) × (25/V) = (1/√28) × (√71 / 1)

300/V = √71 / √28

V = (300 × √28) / √71

V = 188.40cm^3

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