deepta and abhinav having weight 450N and 350N are playing seesaw. If deepta sits at a distance of 2cm from fulcrum, how far should abhinav be seated in order to balance feel ya?

The distance Abhinav should be seated from the fulcrum in order to balance the seesaw is 2.57 cm

Explanation:

For mechanical advantage of a seesaw, we have

Work done by Deepta = Work done by Abhinav

Weight of Deepta × Distance of Deepta from fulcrum = Weight of Abhinav × Distance of Abhinav from fulcrum

The given information are;

The weight of Deepta = 450 N

The weight of Abhinav = 350 N

The distance of Deepta from the fulcrum = 2 cm = 0.02 m

The distance of Abhinav from the fulcrum = X

Which gives;

450 × 0.02 = 350 × X

X = 450 × 0.02/350 = 0.0257 m = 2.57 cm

Therefore, Abhinav should be seated at 2.57 cm from the fulcrum in order to balance the seesaw.

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