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Health, 17.10.2020 20:01 iilovejohnccena1022

Given the function g(x) = 41x3 + a for some constant a, which describes the inverse function g–1(x)? no restriction on the domain of g(x); inverse is g–1(x) = RootIndex 3 StartRoot StartFraction x minus a Over 41 EndFraction EndRoot
no restriction on the domain of g(x); inverse is g–1(x) = (StartFraction x minus a Over 41 EndFraction) cubed
domain of g(x) restricted to x ≥ 0; inverse is g–1(x) = RootIndex 3 StartRoot StartFraction x minus a Over 41 EndFraction EndRoot
domain of g(x) restricted to x ≥ 0; inverse is g–1(x) = (StartFraction x minus a Over 41 EndFraction) cubed

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