Use a punnett square to determine the possible genotypes of The offspring of a BB x bb cross A genotypes
B phenotypes
C percent chance for each
Whoever answers will Mark brainlessness

Answer in explanation

Explanation:

Since both parents only carry 1 type of allele ( dominant or recessive ), the offspring would have to be heterozygous according to the punnett square.

a) there is only 1 possible genotype : Bb there is a 100% chance for this

Because the dominant allele, in this case B, always shows in the phenotype, the phenotypic ratio would be 1:0. The recessive allele, b, only shows up if both parents pass along a recessive allele.

b) The offspring has a 100% chance of exhibiting trait B

I hope this helps, good luck!

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