What was the decision and what was the vote tally of the supreme court judges in the brown v. board of education case?

Brown v. Board of Education of Topeka was a landmark 1954 Supreme Court Case in which it was ruled unanimously that racial segregation of children in public schools was unconstitutional.

The Supreme Court has nine justices. This vote was unanimous, meaning that all justices voted the same way.

The plaintiff, Oliver Brown, filed a lawsuit against the Board of education of Topeka, Kansas. His daughter, Linda Brown, was denied access to Topeka's white school which was located close to her home. Instead, she had to walk six blocks to catch her school bus to ride 1 mile to her segregated black school.

In his lawsuit, Brown claimed that this segregation violated the so called 'equal protection clause' of the 14th Amendment that guarantees equal protection of the laws to every person.

b). (sounds as the best answer)

i believe the answer is:

-   william jennings bryan is a democrat while mckinley was a republican

at that time, the segment of population that choose for democratic party were the voters with low economic background and vice versa

- william jennings has support of populists and wants to have inflation to farmers while mckinley has support of bankers and businessmen , doesn't want inflation

the fixed value of gold make the large business able to stack up their gold without   being worried that it would devaluated.

- william jennings supported the silver standard while mckinley supported the gold standard

according to jenning, using other metal beside gold could the poor people to have more purchasing power and them advance in the society.