6) Jimmy's school is selling tickets to a play. On the first day of ticket sales the school sold 6 adult
tickets and 8 child tickets for a total of $50. The school took in $53 on the second day by selling
7 adult tickets and 8 child tickets. Find the price of an adult ticket and the price of a child ticket.

Let “x” be the cost of an adult ticket
let “y” be the cost of a child ticket
1st day: 50=6x+8y
2nd day: 53=7x+8y
Let both equations equal 0
0=6x+8y-50
0=7x+8y-53
Let equation 1 =equation 2
6x+8y-50=7x+8y-53
Isolate x
7x-6x=53-50+8y-8y
x=3
substitute x=3 into equation 1
6(3)+8y=50
y=4
Therefore the cost of a child ticket is $3 and the cost of an adult ticket is $4

Ithink the answer is d but don’t answer it. i need points.