If a sample of helium occupies 15.9 mL at 0.885 kPa what volume will it occupy at 0.500 kPa

V2 = 28.143 mL

28.143 mL will occupy 0.500 kpa

Explanation:

Let v1 = 15.9 ml

P1 = 0.885 kpa

P2 = 0.500 kpa

V2= ?

Boyle's law

Using p1v1=p2v2

V2 =( p1v1)/(P2)

V2 =( 15.9*0.885)/0.5

V2 = 14.0715/0.5

V2 = 28.143 mL

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