How to write y=-1 into slope and y-intercept form?

y= 0x+-1 or y=0x-1

Explanation:

it is in slope intercept form already, because the 0 ans x cancel out bc 0 times anything is 0.

Using the slope-intercept form, the slope is 0.

The y-intercept form is y=mx+b. So, mx is slope, and b is the intercept. You would then have -1=0x+b and you would just have to use a graph to solve for the intercept.

Hope this helps!!:)

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