A cat that weighs 55 N sits on the top of a cat tree. It is 2 m above a 110 N dog. How does the mass of the animals relate to the force of gravity on
them?
O A. The mass of the 55 N cat will be the same as the mass of the 110
N dog after it jumps to the ground

.
B. The 55 N cat has less mass than the 110 N dog.
C. The 55 N cat has the same mass as the 110 N dog when it is in
the cat tree.
O D. The mass of the 55 N cat is greater than the mass of the 110 N
dog.

B. The 55 N cat has less mass than the 110 N dog.

Explanation:

Given;

weight of the cat, W₁ = 55 N

Weight of the dog, W₂ = 110 N

distance between the cat and the dog, d = 2 m

The acceleration due to gravity (g) acting on both animals is the same irrespective of their different positions.

g = 9.8 m/s²

Force of gravity, F = W = mg

where;

m is the mass of the animals

The mass of the cat = m₁ = W₁/g

                                     m₁ = 55/9.8 = 5.6 kg

The mass of the dog = m₂ = W₂/g

                                      m₂ = 110/9.8 = 11.22 kg

Therefore, it can be seen that the mass of the cat is less than the mass of the dog.

d

step-by-step explanation:

look at the x and y axis

the section of the chart that represents a point at which a bill needs approval from a majority of people in both chambers to advance is j, as this is the only section before the bill becomes law which has both rows (symbolizing the chambers) converging into one, meaning that the two parts of the congress have to approve of it before it can march on with the process.