What additional information can be used to prove δfeg ≅ δfqg by sas?

∠EFG=∠QFG

Step-by-step explanation:

In the given picture we have two triangles ΔFEG and ΔFQG  in which EF=FQ

and GF=GF [ by reflexive property].

To apply SAS postulate we need included angle of sides EF, GF and FQ, GF.

Therefore, the additional information can be used to prove ΔFEG ≅ ΔFQG is given by :-

∠EFG=∠QFG

250

step-by-step explanation:

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for