Aplayer gets to throw 4 darts at the target shown. assuming the player will always hit the target, the probability of hitting an odd number three times is *blank* times more than the probability of hitting an even number 3 times

The probability of hitting an odd number three times is times more than the probability of hitting an even number 3 times.

Step-by-step explanation:

From the given picture , the total total number of sections in the spinner = 5

Sections having Odd numbers = 3

Sections having Even numbers =2

We know that ,

So , probability of hitting an odd number =

Probability of hitting an even number =

Since all events are independent of each other ,

So , probability of hitting an odd number three times =

Probability of hitting an even number three times =

Divide   by , we get

Hence, the probability of hitting an odd number three times is times more than the probability of hitting an even number 3 times.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)