Two cyclists leave town at the same time on the same road going in   the same direction. cyclist a is going 6 miles per hour faster than cyclist b. after 8 hours, cyclist a has traveled three times the distance as cyclist b. use the equation 24x= 8(x+6) to find how fast cyclist b was traveling.

3 mph

Step-by-step explanation:

Two cyclists leave town at the same time on the same road going in  the same direction.

Cyclist A is going 6 mph faster than cyclist B

Let speed of cyclist B be x mph

Speed of cyclist A be (x+6) mph

Both cyclist leave town at the same time and traveled 8 hours.  

After 8 hours cyclist A has traveled 3 times the distance as cyclist B

Therefore, 8(x+6) = 3(8x)

8x + 48 = 24x

24x - 8x = 48

       16x = 48

          x = 3 mph

Hence, The speed of cyclist B was 3 mph

2: 10

step-by-step explanation:

38 was the other number of your question.