Set up an integral to find the length of the path x = sin(t), y = sin2 (t). hint: first you need to find an interval that traces the path exactly once.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: f = 32.2m

step-by-step explanation: that is the answer