Solve the systems of equations algebraically 4x+5y=15 -4x+6y+7 answers a- (5/4, 2) b- (2, 5/4) c- (4/5,2) d (2, 4/5)

STEP 1:
4x + 5y= 15
-4x + 6y= 7
add the two above equations; the x term cancels out; solve for y

11y= 22
divide both sides by 11

y= 2

STEP 2:
substitute the y value in step 1 into either original equation

4x + 5y= 15
4x + 5(2)= 15

4x + 10= 15
subtract 10 from both sides

4x= 5
divide both sides by 4

x= 5/4

ANSWER: (A) x= 5/4, y= 2 or (5/4, 2)

Hope this helps! :)