1) in a trapezoid abcd with legs ab and cd , the diagonals intersect each other at point o. compare the areas of: δabd and δacd and then 2) in a trapezoid abcd with legs ab and cd , the diagonals intersect each other at point o. compare the areas of: δabo and δcdo pleaee

1)  Area of ΔABD = Area of ΔACD and

2)  Area of ΔABO = Area of ΔCDO

Step-by-step explanation:

1) In the given trapezoid ABCD,

AD || BC

Triangles ΔABD and ΔACD lie on the same base AD and lie between the parallel lines AD and BC.

Hence, they are equal in area.

Therefore, Area of ΔABD = Area of ΔACD.

2) From 1), we have

Ar (ΔABD) = Ar(ΔACD)

Subtract Ar (ΔAOD) from both sides,

Ar (ΔABD) - Ar (ΔAOD) = Ar(ΔACD) - Ar (ΔAOD)

Ar (ΔABO) = Ar (ΔCDO)

the answer will be b x² +x-1

step-by-step explanation:

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step-by-step explanation: