(! ) ian tosses four fair coins and writes down all the possible outcomes. after creating the sample space for his experiment, he decides to find the probabilities of different events. arrange the events in order of their probability from least to greatest.

The correct order is:
the probability of heads on 2nd and 4th toss only; 
the probability of at least 3 tails in a row; 
the probability of 3 or more heads;
the probability of consecutive tails; and 
the probability of at least 2 tails.

There are 16 outcomes in the sample space.

There are 8 ways of having consecutive tails; this gives the probability 8/16.
There is 1 way of having heads on the 2nd and 4th toss only, making the probability 1/16.
There are 3 ways to have at least 3 tails in a row, making the probability 3/16.
There are 11 ways to have at least 2 tails, making the probability 11/16.
There are 5 ways to have at least 3 heads, making the probability 5/16.

The answer is: a = about 63.59ft2 for 15