The sum of a student's three score is 246. if the first is 14 points more than the second, and the sum of the first two is 6 more than twice the third, what was the first score?

Let the second score = x
⇒ second score = x

the first is 14 points more than the second
⇒ first score = x + 14

the sum of the first two is 6 more than twice the third
⇒ third score = 1/2 (x + x + 14 - 6) = x + 4

The sum of a student's three score is 246
⇒ x + (x + 14) + (x + 4) = 246

Solve x:
x + x + 14 + x + 4 = 246
3x + 18 = 246
3x = 228
x = 76

second score = x = 76
first score = x + 14 = 76 + 14 = 90

90