Mathematics, 20.07.2019 15:00 pc103919
Find the area in the first quadrant under the curve y = 1 / (x^2+6x+10)
Answers: 1
, so that 
. Then as 
, we have 
; as 
, we have 
. So the integral becomes
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Find the area in the first quadrant under the curve y = 1 / (x^2+6x+10)...
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