Abasket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. jack picks a fruit at random and does not replace it. then bethany picks a fruit at random. what is the probability that jack gets a peach and bethany gets an orange?

Hello!

You have to find the probabilities of them happening separately

To do this you do the amount of favorable outcomes over the total amount of outcomes

3 + 2 + 2 + 2 + 5 = 14 total fruit

The chance of Jack getting a peach is 5 / 14

The chance of Bethany getting an orange is 2 / 13 because Jack did not put the fruit back in so their is one less to choose from

You multiply the two probabilities to find the probability of them happening in a row

5/14 * 2/13 = 5/91

The answer is 5/91

Hope this helps!

7p=14 so then you would divide by p=2