How do i solve this stats question? based on a survey of a random sample of 900 adults in the united states, a journalist reports that 60 percent of adults in the united states are in favor of increasing the minimum hourly wage. if the reported percent has a margin of error of 2.7 percentage points, which of the following is closest to the level of confidence? (a) 80.0% (b) 90.0% (c) 95.0% (d) 95.5% (e) 99.0%

We have the following data:

Margin of Error = E = 2.7 % = 0.027
Sample size = n = 900
Proportion of adults in favor = p = 60% = 0.6

We need to find the confidence level. For this first we need to find the z value.

The margin of error for a population proportion is given as:



Using the values, we get:



As, seen from the z table, z=1.65 corresponds to the confidence level 90%. So, the answer to this question is option B

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