Given that angle dab and angle dcb are right angles and measure bdc = 54°, what is mcad? (the figure is not drawn to scale.) a. 342 b. 216 c. 324 d. 288

 The arc mCAD is 288.

Given: DAB and DCB are right angles; BDC = 54°
Required: arc mCAD
Solution:
 (2 x 54°) + (2 x 54°) + (2 x 36°) = 288
 
Note: in getting 36°, deduct 54° and 90° (right angle) from 180° (which is the total degrees inside a triangle)
   = 180° - 54° - 90°
   = 36° - this is the angle CBD or angle ABD

Dwould be the answer