Instructions: select the correct answer from each drop-down menu. the side length of the square in the figure is 8 cm. the radius of the inscribed circle is [ (32)^(1/2), 16, 4, 32 ] cm, and the radius of the circumscribed circle is [ (32)^(1/2), 2(32)^(1/2), (128)^(1/2), 128 ] cm.

From the figure, the inscribed circle is the circle inside the square. So, the radius of the inscribed circle is half the side of the square. That is 4 cm.

The circumscribed circle is the circle outside the square and its radius is half the diagonal of the square.  Since the square has a side length of 8 cm, the diagonal is computed as follows, using Pythagorean Theorem using half of the square taking the diagonal as the hypotenuse.
     

The radius is half the diagonal. So, the radius is
       or (32)^(1/2).

The scale factor between the two triangles is so x is so x =9