Students in three levels of art classes participated in the regional art competition. the two-way table below shows the number of pieces entered that were created using different media along with the level of the students who submitted the piece. paint clay pastels digital total art 1 43 22 26 12 103 art 2 34 37 14 24 109 art 3 22 20 18 28 88 total 99 79 58 64 300 order the relative frequencies from least to greatest. tiles the percentage of clay pieces entered by art 3 studentsthe percentage of all entries that were painted by art 1 studentsthe percentage of art 2 students who entered digital pieces sequence , ,

The relative frequencies, from least to greatest, would be:

The percentage of all entries painted by Art 1 students (14.33%), the percentage of Art 2 entries that were digital (22.02%), and the percentage of clay entries done by Art 3 students (25.32%).

Explanation
The percentage of clay entries done by Art 3 students:  There are 20 clay entries done by Art 3 students, out of 79 clay entries; 20/79 = 25.32%

The percentage of all entries painted by Art 1 students:  There are 43 entries painted by Art 1 students out of 300 total; 43/300 = 14.33%

The percentage of Art 2 entries that are digital:  There are 24 Art 2 digital entries out of 109 total Art 2 entries; 24/109 = 22.02%

Answer: 10pi

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

A= b/2 because u simplying both sides of equation