Charles wants to determine which car is the fastest. the actual speed of four cars is shown below:

car: a b c d
speed (in km/h): 60.34 60.32 60.33 60.35

if the speedometer can only measure to the nearest tenth of a second, which car will have a different measurement?

Car D

Step-by-step explanation:

Given :  

Car:                           A               B               C                  D

Speed (in km/h):    60.34        60.32       60.33           60.35

To find : which car have different measurement

Speedometer can only measure to the nearest tenth of a second

If the decimal part of the value is greater than or equal to 5 - digit is rounded off  

If the value is less than 5 - digit remain same

Now, we round of all the cars speed

Car A : 60.34 = 60.3

Car B : 60.32 = 60.3

Car C : 60.33 = 60.3

Car D : 60.35 = 60.4

Therefore, Car D is having different measurement.

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.