Ateacher randomly assigns her 30 students 4-digit i. d. numbers using the digits 0 to 9. no digits are repeated within an id number. what is the probability one of those id numbers is 9876?

Step-by-step explanation:

Given:

Number of students: 30

Student ID = 4 digit (0 - 9 without repetition within an ID)

Required:

Calculate the probability that one of those ID numbers is 9876?

Step 1: First we calculate the total possible IDs.

To do this, we make use of the permutation formula; We're using this formula because the question says assign

Hence, Number of possible IDs is as follows;

Where n = digit 0 - 9 = 10 digits

r = 4 digits

becomes

Step 2: Calculate the required probability

Probability is calculated as number of required outcomes divided by number of total outcomes

There are only 1 possibility of having a 9876 out of a total of 5,040

Hence, the probability of having one of those ID numbers as 9876 =

answer: it is 1: 47 pm

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a