Acircle has a radius of 12 cm. find the area of the smaller segment of the circle determined by a 60 degree arc

For this case the area of the circle segment is given by:
 A = (S '/ S) * (pi) * (r ^ 2)
 Where,
 S '/ S: relationship of arcs
 r: radius of the circle
 Substituting values:
 A = (60/360) * (3.14) * ((12) ^ 2)
 A = 75.36 cm ^ 2
 
 The area of the smaller segment of the circle determined by a 60 degree arc is:
 A = 75.36 cm ^ 2

Y=-2x-6 is the answer