Circle 1 is centered at (−4, 5) and has a radius of 2 centimeters. circle 2 is centered at (2, 1) and has a radius of 6 centimeters. what transformations can be applied to circle 1 to prove that the circles are similar? enter your answers in the boxes. the circles are similar because you can translate circle 1 using the transformation rule ( , ) and then dilate it using a scale factor of

Basically, you have two circles. You are asked to take circle 1 and "move it" so that it is on top of circle 2. This process of moving is called a translation and can be thought of as sliding. You do this by ensuring that the two have the same center. So, starting at (-4,5) how do you have to move to end up at (2,1)?

To do this we need to move right 6 as the x-coordinate goes from -4 to 2. We also need to move down 4 as the y-coordinate goes from 5 to 1. So we add 6 to the x-coordinate and subtract 4 from the y-coordinate. The transformation rule is (x+6, y-4).

Once you do this the circles have the same center. Next you wish to dilate circle 1 so it ends up being the same size at circle 2. That means you stretch it out in such a way that it keeps its shape. Circle 1 has a radius of 2 centimeters and circle 2 has a radius of 6 centimeters. That is 3x bigger. So we dilate by a factor of 3.

Translations and dilations (along with reflections and rotations) belong to a group known as transformations.

a - base

b - exponent

so,

the base is 8the exponent is 3the exponent tells you to multiply 8 together three timesthe expanded form is 8*8*8