Mathematics, 19.07.2019 06:00 YaBoiMando2061
Solve this system of equations using a matrix inverse, x+y=10 2x-z=9 y-3z=-5
Answers: 1
![\left[ \begin{array}{ccc}1&1&0\\2&0&-1\\0&1&-3\end{array}\right]\cdot \left[ \begin{array}{c}x\\y\\z\end{array} \right] = \left[ \begin{array}{c}10\\9\\-5\end{array} \right]](/tpl/images/0106/8032/4be0e.png)
![\left[ \begin{array}{c}x\\y\\z\end{array} \right] = \left[ \begin{array}{ccc}1&1&0\\2&0&-1\\0&1&-3\end{array}\right]^{-1}\cdot \left[ \begin{array}{c}10\\9\\-5\end{array} \right]](/tpl/images/0106/8032/4d04b.png)
![\left[ \begin{array}{c}x\\y\\z\end{array} \right] = \dfrac{1}{7}\cdot \left[ \begin{array}{ccc}1&3&-1\\6&-3&1\\2&-1&-2\end{array}\right]\cdot \left[ \begin{array}{c}10\\9\\-5\end{array} \right] = \left[ \begin{array}{c}6\\4\\3\end{array} \right]](/tpl/images/0106/8032/35d37.png)
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Solve this system of equations using a matrix inverse, x+y=10 2x-z=9 y-3z=-5...
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