To approach the runway, a pilot of a small plane must begin a 10 degree descent from a height of 1790 feet above the ground. to the nearest tenth of a mile, how many miles away from the runway is the airplane at the start of this approach?

2.0 miles.

Step-by-step explanation:

Let x be the distance from the runway and airplane at the start of this approach.

We have been given that to approach the runway, a pilot of a small plane must begin a 10 degree descent from a height of 1790 feet above the ground.

We will use sine to solve our given problem as sine relates opposite side of a right triangle to its hypotenuse.

Upon substituting our given values in above formula, we will get:

To convert the distance into miles, we will divide our distance in feet by 5280 as one mile equals to 5280 feet.

Upon rounding our answer to the nearest tenth of a mile we will get,

Therefore, the airplane is approximately 2.0 miles away from the runway at the start of this approach.

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step-by-step explanation: