The equation h(t)=−16 t 2 +19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. what is the initial velocity when the rock is thrown? enter your answer in the box.

For this case we have an equation of the form:
 h (t) = (1/2) * a * t ^ 2 + vo * t + h0
 Where,
 a: acceleration
 vo: initial speed
 h0: initial height
 t: time
 We have then that the equations:
 h (t) = - 16t ^ 2 + 19t + 110
 Therefore, the initial velocity is given by:
 vo = 19 feet / s
 
 The initial velocity when the rock is thrown is:
 vo = 19 feet / s