Select the exclusion that fits best with this problem. 3x^2y^2-6xz/6x^2yz choices x = 0 x, y, z = 0 1 + y + y^2, y = 0, 1 - y = 0 a, b = 0, a^2 + ab + b^2 = 0 2x - 1 = 0, 4x^2 + 2x + 1 = 0

Option B is correct .i.e., x , y , z = 0 must be excluded.

Step-by-step explanation:

Given Expression:

We have to find value of x , y and z which are to be excluded.

Value of variable of a expression are excluded for which expression does not exist.

Given expression is of fraction,

so, where denominator is going to be zero those value going to be excluded.

Here Denominator = 6x²yz

Denominator can not be equal to 0

So to find point where it become zero we put 6x²yz equal to 0

6x²yz = 0

⇒ x² = 0  or y = 0 or z = 0

Therefore, Option B is correct .i.e., x , y , z = 0 must be excluded.

u bout ugly as   a mf

step-by-step explanation: lol