Use the distributive property to find the products for 3-11 3: (x+1) (x+3) 4: (y+6) (y+4) 5: (z-5) (z+3) 6: (a+8) (a-3) 7: (g-7) (g-2) 8: (n-6) (n-4) 9: (3m+1) (m+9) 10: (2p-4) (3p+2) 11: (6-5s) (2-s)

3: (X + 1) (X + 3)
    = (x + 1)(x + 3)
    = (x)(x) + (x)(3) + (1)(x) + (1)(3)
    
    = X^2 + 3X + X + 3
    = X^2  + 4x  + 3

4:
(y + 6) (y + 4)
= (y + 6)(y + 4)
= (y)(y) + (y)(4) + (6)(y) + (6)(4)

= y^2 + 4y  + 6y + 24
= y^2 + 10y + 24

5:
(z - 5) ( (z + 3)
= (z +  - 5)(z + 3)
= (z)(z) + (z)(3) + ( - 5)(z) + ( - 5)(3)

= z^2 + 3z - 5z - 15
= z^2 - 2z - 15

6:
(a + 8) (a -3)
= (a + 8)(a +  - 3)
= (a)(a) + (a)( - 3) + (8)(a) + (8)( - 3)

= a^2 - 3a + 8a - 24
= a^2 + 5a - 24

7:
(g - 7) ( g - 2)
= (g +  - 7)(g  +  - 2)
= (g)(g) + (g)( - 2) + ( - 7)(g) + ( - 7)( - 2)

= g^2 - 2g - 7g + 14
= g^2 - 9g + 14

8:
(n - 6) (n - 4)
(n +  - 6)( n +  - 4)
= (n)(n) + (n)( - 4) + ( - 6)( n) + (- 6)( - 4)

= n^2 - 4n - 6n + 24
= n^2 - 10n + 24

9:
(3m + 1) ( m + 9)
= (3m + 1)(m + 9)
= (3m)(m) + (3m)(9) + (1)(m) + (1)(9)

= 3m^2 + 27m + m + 9
= 3m^2 + 28m + 9

10:
(2p - 4) ( 3p + 2)
= (2p +  - 4)(3p + 2)
= (2p)(3p) + (2p)(2) + ( - 4)(3p) + (- 4)(2)

= 6p^2 + 4p - 12p - 8
= 6p^2 - 8p - 8

11:
(6 - 5s) (2 - s)
= (6 +   - 5s)(2 +  - s)
= (6)(2) + (6)( - s) + ( - 5s)(2) + (- 5s)( - s)

= 12 - 6s - 10s + 5s^2
= 5s^2 - 16s + 12

Hope that helps wowzah….my brain is tired nowhave a good day...

Ithink the answer is b i hope it my friend message me if i’m wrong and i’ll change my answer and fix it for you

No he does not because he can only cover 12 square feet from 15 square feet which he will still need 3 more. this is because if 3×5=15 square feet and 15-12=3 which thats the answer