Mathematics, 18.07.2019 17:00 Casey7019

The standard diameter of a golf ball is 42.67 mm. a golf ball factory does quality control on the balls it manufactures. golf balls are randomly measured to ensure the correct size. one day, an inspector decides to stop production if the discrepancy in diameter is more than 0.002 mm. what is the range of acceptable values?

Answers: 1

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Answers

The lower end of the range is
42.670 - 0.002 = 42.668 mm

The upper end of the range is
42.670 + 0.002 = 42.672 mm

The range of acceptable values is 42.668 mm to 42.672 mm.

Answer from: Loggtech24

The range of acceptable values of golf ball = 42.668 mm- 42.672 mm.

Step-by-step explanation:

Given

Diameter of golf ball= 42.67 mm

An inspector decides to stop the production if Discrepency in diameter= More than 0.002 mm

Diameter: It is the longest chord of circle which divides the circle into two equal halves .

Range: It is defined as the value lies between least value and higher value .

Lower end of the range= 42.67 -0.002

By using subtitution property of equality

Lower end of the range= 42.668 mm.

Bu using subtraction property of addition

Upper end of the range = 42.67+ 0.002

By using substitution property of equality

Upper end of the range = 42.67+0.002= 42.672 mm.

By using addition property of equality.

Hence, the range of acceptable values of golf ball =42.668 mm-42.672 mm.

Answer from: Quest

It would be the second one because it passes the vertical line test
Which graph represents a function?

Answer from: Quest

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

$ab^2+ac^2=bc^2$

$ab^2+ac^2=x^2$ )

triangle abd and cba are similar,

$\frac{ab}{bc}=\frac{bd}{ab}$

$ab^2=bc\cdot bd$

$25=bc\cdot bd$ (2)

triangle cad and cba are similar,

$\frac{ac}{bc}=\frac{cd}{ac}$

$ac^2=bc\cdot dc$

$7\times 7=bc\cdot dc$

$49=bc\cdot dc$ )

using (1), (2) and (3), we get

$25+49=x^2$

$74=x^2$

hence proved.

therefore option 2 is correct.

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