1)circle 1 is centered at (−4, 5)(−4, 5) and has a radius of 2 centimeters. circle 2 is centered at (2, 1)(2, 1) and has a radius of 6 centimeters. what transformations can be applied to circle 1 to prove that the circles are similar? enter your answers in the boxes. the circles are similar because you can translate circle 1 using the transformation rule (, ) and then dilate it using a scale factor of . 2)the sector of a circle with a 12-inch radius has a central angle measure of 60°. what is the exact area of the sector in terms of π ?

Figures of same shape and size are similar .Two circles  C1&C2 will be similar.

Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y  is having a translation of y-4.The center of the circle is dilated by 3 units.

The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.

2) Area of sector = ÷360.

Where α is the angle made at center.

Area of given sector= π(12)(12)(60)÷360 =24π.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation: