If (2 − 3i) + (x + yi) = 6, what is x + yi? 4 + 3i 4 − 3i -4 − 3i -4 + 3i 4x + 3i

If (2 − 3i) + (x + yi) = 6, to get x + yi we subtract (2-3i) from both sides of the equation.

(2 − 3i) + (x + yi) - (2 − 3i) = 6 -(2 − 3i) 
(x + yi) = 6 - (2 - 3i)
Open the parenthesis taking care of the signs 
(x + yi) = 6 - (2 - 3i)
            = 6 - 2 + 3i
            = 4 + 3i

The answer is 25uthere is no v in the question

What the heck i didn’t know