According to the intermediate value theorem, if a polynomial has points: (0,10) and (6, -8) f(2) is a value between 0 and 6 f(3) is a value between 10 and -8 f(4) is not a value between 0 and 6 f(5) is not a value between 10 and -8

The IVT would say that for a continuous function on an interval , we can guarantee that for some value of we have or , depending on how behaves over the given interval.

If the polynomial passes through (0, 10) and (6, -8), then we know there is some such that . In that case, only the second option makes sense. We can't claim to know anything about how behaves between values of 0 and 6, only between the values of -8 and 10, so we ignore the first and third options. The fourth scenario is possible, but not something we can guarantee because the IVT doesn't make claims about what is not possible.

No he does not because he can only cover 12 square feet from 15 square feet which he will still need 3 more. this is because if 3×5=15 square feet and 15-12=3 which thats the answer