Last question the figure below shows triangle abc on the coordinate plane. write the coordinates of the vertices of a triangle a'b'c' that results from a translation of triangle abc two units to the right and four units down . a'(   b'(   c'(  

A'(4,-6) , B'(0,1), C'(-2,-2)

Step-by-step explanation:

From the given graph the coordinates of ΔABC area A (2,-2), B(-2,5) and C(-4,2)

If a translation is applied on ΔABC two units to the right and four units down  to create ΔA'B'C'.

Then to find the coordinates of ΔA'B'C' will be we need to apply the translation rule

Now,

and

step-by-step explanation:

try remembering the steps

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are