The length of one side of a square is represented by the function s(x) = 3x – 2. what is the area of the square in terms of x? a.  (s^2)(x) = 9x^2 – 12x + 4b.  (s^2)(x) = 9x^2 + 4  c.  (s^2)(x) = 9x^2 – 36x + 4d.  (s^2)(x) = 9x^2 – 36x + 4

We know that
the area of a square=b²
where 
b is the side length of the square

in this problem
the length of one side of a square is represented by the function
S(x) = 3x – 2
so
Area of the square=[S(x)]²> (3x-2)²> 9x²-12x+4

the answer is the option 
A. (S^2)(x) = 9x^2 – 12x + 4

Iam guessing c. or d.