Can someone answer these two questions : ). no dum answers don’t just answer cuz you want points

A) 1.You must apply the formula for calculate the area of a regular polygon:
 A=Pa/2
 P  is the perimeter
 a is the apothem
 2.Solve for a:
 a=2A/P
 a=2(13.60 cm²/(2.25 cm²x8)
 a=1.51 cm (Apothem)
b)Tan^-1(A°)=7/13
 A°=28.30°
 Tan^-1(B°)=13/7
 B°=61.69°

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12