Suppose that $2300 is initially invested in an account at a fixed interest rate, compounded continuously. suppose also that, after two years, the amount of money in the account is $2519. find the interest rate per year.

The formula for compound continuously rate . 
Where is A (future amount) = 2519, P (initial amount) = 2300, e is the mathematical constant, r (rate of interest) which is unknown, and t (time in years) = 20

Now we plug in the variables into the equation.



It is asking for the rate, so must isolate .

First we divide 2300 on both sides of the equation.




Then we enter the inverse of , which is log.




Then divide  on both sides.




Then divide 20 on both sides.




Finally solve for 

0 = r

The answer is r = 0%

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5